5 3
1 2
2 3
4 5
2
1 3
1 4

YES
NO

n,m=map(int,input().split())
parent=list(range(n+1))
def find(x):
    if parent[x]!=x: parent[x]=find(parent[x])
    return parent[x]
def union(x,y): parent[find(x)]=find(y)
for _ in range(m):
    a,b=map(int,input().split()); union(a,b)
q=int(input())
for _ in range(q):
    a,b=map(int,input().split())
    print('YES' if find(a)==find(b) else 'NO')